Question

A train moving with a speed of 54km/he,when applied brake comes to rest within a distance of 225m.calculate the retardation produced in the train.

Answer 1

here is your answer

given :

initial velocity (u) = 54 km/hr = 54*(5/18) = 15 m/s

final velocity (v) = 0

distance travelled (s) = 225 meter

to find : retardation

solution :

by using 3rd equation of motion

v² = u²+2as

0 = (15)²+2*a*225

450a = -225

a = -0.5 m/s²

so, retardation of train will be -0.5 m/s².

Answer 2

$\huge\underline\pink{\tt Hey \: mate }$

Answer:

initial velocity = 54 km/hr = 15 m/s

final velocity = 0

distance = 225m

Now,

v² = u² + 2as

So,

0 = 225 + 2 × a × 225

-225 = 450a

So acceleration is - 0.5m/s²

$\huge\underline\blue{\tt Thank\: u }$