A train moving with a velocity of 20 m/s is brought to rest by applying brakes in 5s.Calculate the retardation.
Answers
Answered by
35
here is your answer
given :
initial velocity (u) = 20 m/s
final velocity (v) = 0
time taken (t) = 5 seconds
to find : retardation
solution :
by using first equation of motion
v = u+at
0 = 20+5a
5a = -20
a = -4 m/s²
so,the retardation of train will be -4 m/s².
given :
initial velocity (u) = 20 m/s
final velocity (v) = 0
time taken (t) = 5 seconds
to find : retardation
solution :
by using first equation of motion
v = u+at
0 = 20+5a
5a = -20
a = -4 m/s²
so,the retardation of train will be -4 m/s².
Answered by
12
Answer:
initial velocity = 20m/s
final velocity = 0
time = 5second
Now
v = u + at
0 = 20 + 5a
a = - 4m/s²
Hence accleration is -4m/s² (Retardation)
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