plzzz ans......Thnk u
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The original price was X rupees.
Let's say the man would have bought N plants
N = (2800/X)
XN = 2800
But now the price is reduced by 1 rupee for each plant. Hence the new price is (X-1) rupees.
Now the man bought 10 more plants than before. Hence he bought (N + 10) plants with 2730 rupees.
So the equation we can form is
N + 10 = (2730/(X-1))
(N+10)(X-1) = 2730
NX + 10X - N - 10 = 2730
2800 + 10X - (2800/X) - 10 = 2730
(2800/X) - 10X = 2800 - 10 - 2730
(2800/X) - 10X = 60
(280/X) - X = 6
280 - X^2 = 6X
X^2 + 6X - 280 = 0
X^2 + 20X - 14X - 280 = 0
X(X + 20)-14(X + 20) = 0
(X - 14)(X + 20) = 0
Now X is 14 or (-20). But X cannot be negative as it is the price of the plant.
Hence X is 14
Let's say the man would have bought N plants
N = (2800/X)
XN = 2800
But now the price is reduced by 1 rupee for each plant. Hence the new price is (X-1) rupees.
Now the man bought 10 more plants than before. Hence he bought (N + 10) plants with 2730 rupees.
So the equation we can form is
N + 10 = (2730/(X-1))
(N+10)(X-1) = 2730
NX + 10X - N - 10 = 2730
2800 + 10X - (2800/X) - 10 = 2730
(2800/X) - 10X = 2800 - 10 - 2730
(2800/X) - 10X = 60
(280/X) - X = 6
280 - X^2 = 6X
X^2 + 6X - 280 = 0
X^2 + 20X - 14X - 280 = 0
X(X + 20)-14(X + 20) = 0
(X - 14)(X + 20) = 0
Now X is 14 or (-20). But X cannot be negative as it is the price of the plant.
Hence X is 14
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