A train moving with velocity of 54 km initiated so that it will ocity becomes 72 km per hour in 15 seconds find the acceleration of the train
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Hi.
Here is your answer---
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Given---
Initial Velocity(u) = 54 km/hr.
Final Velocity(v) = 72 km/hr.
Time(t) = 15 seconds.
Using the Formula,
Acceleration = (v - u)/t
= (72 - 54)/15
= 18/15
= 6/5
= 1.2 km/s².
= 1200 m/s².
Thus, Acceleration Produced by the Car is 1200 m/s².
___________________
Hope it helps.
Have a nice day.
Here is your answer---
___________________
Given---
Initial Velocity(u) = 54 km/hr.
Final Velocity(v) = 72 km/hr.
Time(t) = 15 seconds.
Using the Formula,
Acceleration = (v - u)/t
= (72 - 54)/15
= 18/15
= 6/5
= 1.2 km/s².
= 1200 m/s².
Thus, Acceleration Produced by the Car is 1200 m/s².
___________________
Hope it helps.
Have a nice day.
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