Question

A train of mass M = 1000 ton is running with a uniform velocity on a level track. Resistance to motion is proportional to the mass being pulled
and pulling force of the engine is a constant. The last carriage of mass m = 200 ton gets decoupled. The driver discovers it after travelling a distancel=100 m and instead of applying brakes, he immediately shuts off the engine. When both the parts of the train come to rest, what is the
distances between them?



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Answer 1

Answer:

Given A train weighing 1000 ton is moving on a horizontal track with a uniform velocity of 10 m/s. the total resistance to the motion of the train is 5 kgf per ton. if g= 10 m/s2, then what is the power of the engine?

Given A train weighing 1000 ton is moving on a horizontal track with a uniform velocity of 10 m/s. the total resistance to the motion of the train is 5 kgf per ton. if g= 10 m/s2, then what is the power of the engine?We know that Resistive force F = m g

Given A train weighing 1000 ton is moving on a horizontal track with a uniform velocity of 10 m/s. the total resistance to the motion of the train is 5 kgf per ton. if g= 10 m/s2, then what is the power of the engine?We know that Resistive force F = m g                                                    = 5 x 1000 x 10

Given A train weighing 1000 ton is moving on a horizontal track with a uniform velocity of 10 m/s. the total resistance to the motion of the train is 5 kgf per ton. if g= 10 m/s2, then what is the power of the engine?We know that Resistive force F = m g                                                    = 5 x 1000 x 10                                                   = 50 K N

Given A train weighing 1000 ton is moving on a horizontal track with a uniform velocity of 10 m/s. the total resistance to the motion of the train is 5 kgf per ton. if g= 10 m/s2, then what is the power of the engine?We know that Resistive force F = m g                                                    = 5 x 1000 x 10                                                   = 50 K NWe know that Power P = force x velocity

Given A train weighing 1000 ton is moving on a horizontal track with a uniform velocity of 10 m/s. the total resistance to the motion of the train is 5 kgf per ton. if g= 10 m/s2, then what is the power of the engine?We know that Resistive force F = m g                                                    = 5 x 1000 x 10                                                   = 50 K NWe know that Power P = force x velocity                                     = 50 K N x 10

Given A train weighing 1000 ton is moving on a horizontal track with a uniform velocity of 10 m/s. the total resistance to the motion of the train is 5 kgf per ton. if g= 10 m/s2, then what is the power of the engine?We know that Resistive force F = m g                                                    = 5 x 1000 x 10                                                   = 50 K NWe know that Power P = force x velocity                                     = 50 K N x 10                              P = 500 K W

Given A train weighing 1000 ton is moving on a horizontal track with a uniform velocity of 10 m/s. the total resistance to the motion of the train is 5 kgf per ton. if g= 10 m/s2, then what is the power of the engine?We know that Resistive force F = m g                                                    = 5 x 1000 x 10                                                   = 50 K NWe know that Power P = force x velocity                                     = 50 K N x 10                              P = 500 K WSo power of engine is 500 KW

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Answer 2

Answer:

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