Question

a train passes a 135 long platform in 90 seconds and a man standing on the platform in 10 seconds find first the speed of the train and second the length of the train​

Answer 1

Answer:

Let the speed of the train be x m/sec and length of the train be y m. Then,

Let the speed of the train be x m/sec and length of the train be y m. Then,Speed of the train

Let the speed of the train be x m/sec and length of the train be y m. Then,Speed of the trainLength of the train

Let the speed of the train be x m/sec and length of the train be y m. Then,Speed of the trainLength of the train

Let the speed of the train be x m/sec and length of the train be y m. Then,Speed of the trainLength of the train = Time taken by the train to pass the man

Let the speed of the train be x m/sec and length of the train be y m. Then,Speed of the trainLength of the train = Time taken by the train to pass the man⇒ xy

=15⇒y=15x ......... (1)

=15⇒y=15x ......... (1)and

=15⇒y=15x ......... (1)and Speed of train

=15⇒y=15x ......... (1)and Speed of trainLength of train + Length of platform

=15⇒y=15x ......... (1)and Speed of trainLength of train + Length of platform

=15⇒y=15x ......... (1)and Speed of trainLength of train + Length of platform = Time taken by the train to cross the platform

=15⇒y=15x ......... (1)and Speed of trainLength of train + Length of platform = Time taken by the train to cross the platform⇒

=15⇒y=15x ......... (1)and Speed of trainLength of train + Length of platform = Time taken by the train to cross the platform⇒ x

=15⇒y=15x ......... (1)and Speed of trainLength of train + Length of platform = Time taken by the train to cross the platform⇒ xy+90

=15⇒y=15x ......... (1)and Speed of trainLength of train + Length of platform = Time taken by the train to cross the platform⇒ xy+90

=15⇒y=15x ......... (1)and Speed of trainLength of train + Length of platform = Time taken by the train to cross the platform⇒ xy+90 =30⇒y+90=30x ........ (2)

=15⇒y=15x ......... (1)and Speed of trainLength of train + Length of platform = Time taken by the train to cross the platform⇒ xy+90 =30⇒y+90=30x ........ (2)Put the value of y from (1) in (2)

=15⇒y=15x ......... (1)and Speed of trainLength of train + Length of platform = Time taken by the train to cross the platform⇒ xy+90 =30⇒y+90=30x ........ (2)Put the value of y from (1) in (2)15x+90=30x⇒15x=90⇒x=6m/sec

=15⇒y=15x ......... (1)and Speed of trainLength of train + Length of platform = Time taken by the train to cross the platform⇒ xy+90 =30⇒y+90=30x ........ (2)Put the value of y from (1) in (2)15x+90=30x⇒15x=90⇒x=6m/sec∴ Speed of train =(6×

=15⇒y=15x ......... (1)and Speed of trainLength of train + Length of platform = Time taken by the train to cross the platform⇒ xy+90 =30⇒y+90=30x ........ (2)Put the value of y from (1) in (2)15x+90=30x⇒15x=90⇒x=6m/sec∴ Speed of train =(6× 5

=15⇒y=15x ......... (1)and Speed of trainLength of train + Length of platform = Time taken by the train to cross the platform⇒ xy+90 =30⇒y+90=30x ........ (2)Put the value of y from (1) in (2)15x+90=30x⇒15x=90⇒x=6m/sec∴ Speed of train =(6× 518

=15⇒y=15x ......... (1)and Speed of trainLength of train + Length of platform = Time taken by the train to cross the platform⇒ xy+90 =30⇒y+90=30x ........ (2)Put the value of y from (1) in (2)15x+90=30x⇒15x=90⇒x=6m/sec∴ Speed of train =(6× 518

=15⇒y=15x ......... (1)and Speed of trainLength of train + Length of platform = Time taken by the train to cross the platform⇒ xy+90 =30⇒y+90=30x ........ (2)Put the value of y from (1) in (2)15x+90=30x⇒15x=90⇒x=6m/sec∴ Speed of train =(6× 518 )km/hr=21.6km/hr.