Question

A train sets off at 2 p.m. at the speed of 70 kmph. another train starts at 3:30 p.m. in the same direction at the rate of 85 kmph. at what time the trains will meet?

Answer 1

Ans: 10:30 pm

Suppose trains meet x hours after 2 pm

First train travels x hours.
Distance covered by first train = 70x

Second train travels (x-1.5) hours.
Distance covered by second train = 85(x-1.5)

Both the distances are same as they meet after x hours
=> 70x = 85(x-1.5)
=> 15x = 127.5
=> x = 8.5 = 8 hour 30 minutes

Therefore, the trains meet 8 hours 30 minutes after 2 pm
i.e., at 10:30 pm

Answer 2

Answer:

10 : 30 pm

Step-by-step explanation:

1st Train .................................2nd Train

2 pm                                     3:30 pm

So, Time gap is = 1 h 30 min, then 1st Train goes

D = Time * Speed

   = 1.5 * 70

   = 105 km

Speed Difference = (85 - 70) = 15 km /h

Time = (105 / 15) h

        = 7 h

They will meet after 7 h

= 3:30 + 7h = 10:30 pm