Question

a train stars rest accelerates uniformly and attains a velocity 48 kmh in 2 mintues.IT taravels at this speed for 5 mintues.
FINally it moves with unifrom retardation and is stopped after 3 minutes find tha total distance travelled by the train

Answer 1

Answer:

sahana

Explanation:

sujana and write your email address so that you doing the sea.

Answer 2

Answer:

I am answering this question by step wise:(1) convert 48km/h to m/s 4 8×1000/3600=13.33m/s .(2) 2 min to second =120 seconds,5 min to seconds= 300 seconds and 3 min to seconds=180seconds. (3) first find the distance of the first part of the journey so, d= s×t = 13.33×120= 1600m. (4) second part of the journey d=13.33×300=4000m. (5) final part of the journey d=13.33×180=2400m . so, total distance= the total of all part of journey (1600+4000+2400)= 8000m.

Explanation:

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