Question

A train start from rest and acceleration uniform at the rate of 5m/ sector for 5 sector calculatewri the velocity of train in 5 sec

Answer 1

Answer:

25 m/s

Explanation:

Given :

• Initial velocity = u = 0 m/s

• Acceleration of the train = 5 m/s²

• Time taken = 5 seconds

To find:

• Velocity of the train after 5 seconds

Using the first equation of motion :

V=u+at

Substituting the values :

V=0+5×5

V=0+25

V=25 m/s

The final velocity of the train is equal to 25 m/s

Answer 2

✯✯ QUESTION ✯✯

A train start from rest and acceleration uniform at the rate of 5m/ sector for 5 sector calculatewri the velocity of train in 5 sec..

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✰✰ ANSWER ✰✰

$\longmapsto\tt{Initial\:Velocity(u)=0m/s}$

$\longmapsto\tt{Acceleration(a)={5m/s}^{2}}$

$\longmapsto\tt{Time=5\:Sec.}$

$\longmapsto\tt{Final\:Velocity=?}$

➥Using 1st Equation of Motion : -

$\longmapsto\tt{\large{\boxed{\bold{\bold{\green{\sf{v=u+at}}}}}}}$

➥Putting Values : -

$\longmapsto\tt{v=0+5\times{5}}$

$\longmapsto\tt{v=0+25}$

$\red\longmapsto\:\large\underline{\boxed{\bf\green{v}\orange{=}\purple{25m/s}}}$

☛So , the final velocity of train is 25m/s..