Question

A train starting from A chest attains availability of 90 km per hour in 3 minute assuming that the acceleration is uniform.find
(i)acceleration
(ii)the distance travelled

Answer 1

heya......


Given :

Initial Velocity=u=0m/s

Final velocity= V= 90km/h

Time =5 min =3/60 h =1/20 h

acceleration=a=?

As we know that , a=v-u/t

⇒a=90-0/1/20

=90*20

=1800km/h²

Distance travelled  =s=ut+1/2at²

=0x1/20 +1/2(1800)(1/20)²

=(1/2)x1800x(1/400)

=2.25km

∴Distance travelled by the train for attaining this velocity 2.25km.


tysm.#gozmit

Answer 2

Heya !!!

Here is your answer.

Given :
u = 0
v = 90 km/h
t = 3 mins = 3 × 1/60 = 1/20 hr.

Using
v = u + at
a = 90/(1/20) = 90 × 20 = 1800 km/h²

Distance travelled =
Using s = ut + 1/2 at²
s = 1/2 × 1800 × 1/20 × 1/20
= 2.25 km

Hope It Helps