Question

A train starting from a railway station and moving with uniform acceleration
attains a speed of 40 km h-1 in 10 minutes. Find its acceleration​

Answer 1

Explanation:

initial velocity=0 ( train is at rest)(u)

final velocity=40km/h(v)

time=10s( t)

acceleration=?(a)

firstly we will put the most suitable equation of motion that is v=u+at

40=0+10a

40=10a

a=40/10

a=4km/hr

but the acceleration is in the form of m/s so we will convert 4km/h

4*5/18

=1.1m/s^2

so the acceleration is 1.1m/s

this is the answer

hope it is helpful to you

Answer 2

Given:-

• Initial velocity of Train (u) = 0m/s
• Final velocity (v) = 40 km/h
• Time (t) = 10 min

To Find :-

What is the acceleration of train ???

Solution :-

Firstly we can convert km/hr into m/s

⇒ 1 km/hr = 5/18

⇒ v = 11.11 m/s

Now, we can convert min into sec$.$

⇒ 1 min = 60 sec

⇒ 60×10 = 600 sec

⇒ t = 600 sec

By using first equation of motion

• v = u + at

where,

Initial velocity = " u "

Final velocity = " v "

Time = " t "

acceleration = " a "

Now, putting the values in the above formula , we get

⇒ 11.1 = 0 + a × 600s

⇒ 11.1 = a × 600

⇒ a = 111/6000

⇒ a = 0.0185 m/s²

therefore,

The acceleration of the train is 0.0185 m/s².

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