Question

A train starting from a railway station and moving with unify Accleration attains a speed of 40 km ${h} ^{-1}$ in 10 minutes. Find its acceleration. ​

Answer 1

$\huge{\pink{\green {\sf\boxed{ANSWER = 0.0185m\:{s}^{-2}}}}}$

$\huge{\pink {\sf\boxed{Step\: by\: step \:explanation}}}$

Given,

Initial velocity, ${u}={0}$

Final velocity, $v=40 km\: {h} ^{-1}=11.11m\:{s}^{-1}$

Time ${(t)} =10 minutes = 60*10 =600 s$

Acceleration ${(a)} ={?}$

We know that ${v} =u + at$

${11.11}=0 + a * 600$

${a}= \frac{11.11}{600}<strong>=\small</strong><strong>{\pink{\green {\sf\boxed{</strong><strong>0.0185m</strong><strong>\</strong><strong>:</strong><strong> </strong><strong>{</strong><strong>s</strong><strong>}</strong><strong> </strong><strong>^</strong><strong>{</strong><strong>2</strong><strong>}</strong><strong>}}}}$

$\Large\boxed{SOLVED}$

Answer 2

Answer:

240 kmh^-2

Step-by-step explanation:

A= (40-0)/ (10/60)                      NOTE :- 10 is divided by 60 to make hours                

  = 40/(1/6)                                               & Final velocity is 40 and Initial                                                                                  =     40*6                                                  velocity is 0.

ANS =240 kmh^-2