A train starting from a railway station and moving with uniform acceleration attains a speed of 50km/hr in 20 minutes.Find its acceleration.
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from the 1st equation of motion we know
acceleration(a)= {final velocity(v)-initial velocity(u)}/time taken(t)
so we have
u= 0 km/hr
v= 50 km/hr
t= 20min = 0.3334 hr
so putting the values we have
a=(50-0)/0.3334
a=50/0.3334
a=149.970005999 km/hr
acceleration(a)= {final velocity(v)-initial velocity(u)}/time taken(t)
so we have
u= 0 km/hr
v= 50 km/hr
t= 20min = 0.3334 hr
so putting the values we have
a=(50-0)/0.3334
a=50/0.3334
a=149.970005999 km/hr
Shivaangi:
But your ans is wrong...
Given that:
Initial velocity,u=0
Final velocity,v=40km/h
Time taken t=10 min=10/60=1/6 hours
Using v=u+at
a=(v-u)/t=(40-0)/(1/6)=240
Initial velocity,u=0
Final velocity,v=40km/h
Time taken t=10 min=10/60=1/6 hours
Using v=u+at
a=(v-u)/t=(40-0)/(1/6)=240
speed here is hive 50
and time is 20 min
Thnks
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