Question

A train starting from a railway station and moving with uniform acceleration altains a speed 40 kmh-1 in 10 minutes .find its acceleration​

Answer 1

Answer:

Explanation:u = Initial speed

v = Final speed

a = Acceleration

t = Time

Given:-

Initial speed of the train, u = 0 km (Because train starts from the rest.

Final speed of the train, v = 40 km/h = \frac{5}{18} × 40 = 11.11 m/s.

Time taken to attain the speed = 10 minutes = 10 × 60 = 600 sec.

To Calculate:-

Acceleration of the train.

Formula to be used:-

⇒ a=\frac{v-u}{t}

Solution:-

Putting all the values, we get

⇒ a=\frac{v-u}{t}

⇒ a=\frac{11.11-0}{600}

⇒ a=\frac{11.11}{600}

⇒ a=0.0185 \: m/s^2

Hence, Acceleration of the train is 0.0185 m/s².

Answer 2

Answer:

so acceleration is 0.018m/s^2

Explanation:

u=0 m/s

v=40 km/ hour =11.1 m/s

t=10 minutes=600 second

we know that

$a = \frac{v - u}{t}$

$a = \frac{11.1 - 0}{600}$

$a = \frac{11.1}{600}$

$a = 0.018m {s}^{2}$

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