Question

A train starting from a railway
station and moving with uniform
acceleration attains a Speed
40 km h-1 in 10 minutes. Find its
acceleration.​

Answer 1

Explanation:

235 m/s² approx

Answer 2

✸Given:-

➧ Initial velocity of Train(u) = 0m/s

➧ Final velocity (v) = 40 km/h = 11.1 m/s

➧ Time (t) = 10 min = 60×10 =600s

✰To Find :-

➧ Acceleration (a) of train ???

✰ Solution :-

By using first equation of motion

★ v = u +at

➠ 11.1 = 0 + a × 600s

➠11.1 = a × 600

➠ a = 111/6000

➠ a = 0.0185m/s²

∴The acceleration of train is 0.0185 m/s².

✰ Additional information ✰

Some equation of motion are:-

$v = u + at$

$s = ut + \frac{1}{2} at {}^{2}$

$v {}^{2} - u {}^{2} = 2as$

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