Question

A train starting from a railway station and moving with uniform acceleration attains a spped 40 kmph in the 10 minutes. Find its acceleration​

Answer 1

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Answer 2

A train starting from a railway station, (means u = 0) and moving with uniform acceleration attains a spped 40 km/h, (means v = 40 km/h) in the 10 minutes, (means t = 10 min). And we have to find its acceleration (a).

Given :

• Initial velocity (u) = 0 m/s
• Final velocity (v) = 40 km/h = $\sf{\bigg(40 \times \dfrac{5}{18}\bigg) = 11.11 \: m/s}$
• Time (t) = 10 min = 600 s.

To Find :

• Acceleration = ?

Solution :

Using Acceleration Formula : $\underline{ \boxed{ \sf{a \: = \dfrac{v - u}{t} }}}$

$\longrightarrow \sf{\dfrac{11.11-0}{600}}$

$\longrightarrow \sf{\dfrac{11.11}{600}}$

$\longrightarrow \sf{0.0185\: m/s^{2}}$

• Hence, the acceleration attained by the train = 0.0185 m/s².