A train starting from a railway station and moving with uniform acceleration attain a speed 40km/hr in 10 minutes. Find its acceleration.
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Speed of the train or (v) = 40km/h
Therefore,40×1000/60×60m/s
=100/9
U=0
T=10min
=600sec
We know that,
v=u+at
Or, 100/9=0+a×600
Or, 100/9=600a
Or, a=100/9×600
Or, a=1/54
So, its acceleration is 1/54
Therefore,40×1000/60×60m/s
=100/9
U=0
T=10min
=600sec
We know that,
v=u+at
Or, 100/9=0+a×600
Or, 100/9=600a
Or, a=100/9×600
Or, a=1/54
So, its acceleration is 1/54
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