Question

A train starting from a railway station and moving with uniform acceleration attains a speed of 40 km/hr^-1 in 10 mins find acceleration ​

Answer 1

Explanation:

sorry is this understandable

Final speed of the train, v = 40 km/h = × 40 = 11.11 m/s. Time taken to attain the speed = 10 minutes = 10 × 60 = 600 sec. Acceleration of the train. Hence, Acceleration of the train is 0.0185 m/s².

Answer 2

Answer:

The acceleration of the bus is 0.0185 m/s².

Explanation:

Given:

• Initial velocity (u) = 0
• Final velocity (v) = 40 km/hr = 40 × 5/18 = 11.11 m/s.
• Time taken (t) = 10 min = 600 s (since 1 min = 60 sec)

To find:

Acceleration.

Solution:

We know that,

Acceleration = (final velocity – initial velocity)/time

⇒ a = (v – u)/t

By keeping the values, we get

⇒ a = (11.1 – 0)/600

⇒ a = 0.0185 m/s².

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