Question

A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h^-1 in 10 minutes .Find its acceleration

Answer 1

initial velocity ( u ) = 0 ( the train STARTS from railway station )
final velocity  ( v ) = 40 km/hr
                      = 11.12 m/s
time taken ( t )     = 10 min 
                     = 600 sec
acceleration = v - u / t
                    11.12 - 0 / 600
                     = 0.01853 m/s²

Answer 2

Answer:

The acceleration value is 0 $m/s^{2}$

Explanation:

$s=\frac{v-u}{t}$

V=40 km/h

U= 40 km/h

T=10 minutes

v-u/t=40-40/10

      =0/10

      =0 m/s^2