A train starting from a railway station and moving with uniform acceleration attains a speed 40 km/hr in 10 minutes. Find its acceleration. (if you know the answer then only give the answer otherwise i will report you ) please give me the answer.
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Answer:- Train starts from railway station, so initial speed, u = 0. Final speed, v = 40 kmh-1. image001. Time t = 10 min. = 10 x 60. = 600 s. Acceleration,.
Train starts from railway station, so initial speed, u = 0.
Final speed, v = 40 kmh-1

Time t = 10 min
= 10 x 60
= 600 s
Acceleration,
Here
Initial velocity (u) = 0
Final velocity (v)=40km/hr
= 40 multiple by 5/18 m/s
= 100/9
=11.11 m/s
Time (t) = 10 min
= 10 multiple with 60 s
= 600 s
Therefore
Acceleration = final velocity — initially velocity / time taken
=11.11 — 0 / 600 m/s sq
= 0.0185 m/s sq
Train starts from railway station, so initial speed, u = 0.
Final speed, v = 40 kmh-1

Time t = 10 min
= 10 x 60
= 600 s
Acceleration,
Here
Initial velocity (u) = 0
Final velocity (v)=40km/hr
= 40 multiple by 5/18 m/s
= 100/9
=11.11 m/s
Time (t) = 10 min
= 10 multiple with 60 s
= 600 s
Therefore
Acceleration = final velocity — initially velocity / time taken
=11.11 — 0 / 600 m/s sq
= 0.0185 m/s sq
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Answered by
1
Acceleration=40-0/10
=4
=4
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