Question

A train starting from a railway station and moving with uniform acceleration attains a speed 40km/h in 10min.find its acceleration.

Answer 1

ANSWER:-

Here

Initial velocity (u) = 0

Final velocity (v)=40km/hr

= 40 multiple by 5/18 m/s

= 100/9

=11.11 m/s

Time (t) = 10 min

= 10 multiple with 60 s

= 600 s

Therefore

Acceleration = final velocity — initially velocity / time taken

=11.11 — 0 / 600 m/s sq

= 0.0185 m/s sq

THANKS!!!

Answer 2

A train starting from a railway station and moving with uniform acceleration attains a speed 40km/h in 10min.find its acceleration.

$u = 0$

$v = 40 \: km \: {h}^{ - 1}$

$a \: =$

$t = 10 \: min = \frac{10}{60} h$

Now by using ⬇️

$v = u + at$

$a = \frac{v - u}{t} = \frac{40 - 0}{ \frac{10}{6} } = \frac{40 \times 60}{10}$

$= 240 \: km/ {h}^{2}$