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1
S = 3n square / 2 + 5n / 3
for 1st term first put n = 1
a= 4
for sum of first 2 term put n= 2
s of 2 terms = 11
2nd term = 11 - 4
= 7
a= 4
d = 3
n=25
25th term =a+ ( n-1) d
= 4 +24 ×3
= 4+72
=76
for 1st term first put n = 1
a= 4
for sum of first 2 term put n= 2
s of 2 terms = 11
2nd term = 11 - 4
= 7
a= 4
d = 3
n=25
25th term =a+ ( n-1) d
= 4 +24 ×3
= 4+72
=76
Answered by
0
Sn= 3n²/2 + 5n/2
S1 = 3*1²/2 +5(1)/2
S1 = 3/2. + 5/2.
S1 = 8/2
S1 = 4
but we know S1 include only one term therefore,
S1 = a1
A1 = 4
similarly put n=2
S2 = 11
S2 - S1 = 11 - 4 = 7
therefore,
A2 = 7
therefore,,
d = A2 - A1
d = 7. - 4
d = 3
so,
A1 = 4 , d = 3
therefore,
A25 = A1+ 24 d
A25 = 4 + 24(3)
= 4 + 72
= 76 answer.....
S1 = 3*1²/2 +5(1)/2
S1 = 3/2. + 5/2.
S1 = 8/2
S1 = 4
but we know S1 include only one term therefore,
S1 = a1
A1 = 4
similarly put n=2
S2 = 11
S2 - S1 = 11 - 4 = 7
therefore,
A2 = 7
therefore,,
d = A2 - A1
d = 7. - 4
d = 3
so,
A1 = 4 , d = 3
therefore,
A25 = A1+ 24 d
A25 = 4 + 24(3)
= 4 + 72
= 76 answer.....
raminder1:
thanks fr brainliest
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