Question

A train starting from a railway station and moving with uniform acceleration attains a speed of 90kmph
in 10min. Find its acceleration.

Answer 1

Answer:

\frac{1}{24}  m/sec^2

Explanation:

given:-

initial velocity = u = 0 because body starts from rest.

final velocity = v = 90 kmph = 25m/sec. ( because 1 kmph = 5/18 m/sec)

time = 10 min = 10*60 = 600 seconds.

let acceleration be a,

now $a = \frac{v-u}{t}$ = $\frac{25-0}{600} = \frac{25}{600} = \frac{1}{24} m/sec^2$

Answer 2

Answer:

The acceleration is 1/24m/s.s.

Explanation:

u=0m/s

v=90km//h

(in m/s)

=90000/3600

=25m/s

t=10min

(in s)

=10×60

=600s

a=v-u/t

=25-0/600

=25/600

=1/24m/s.s.