A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h−1 in 10 minutes. Find its acceleration.
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Answer:
Final speed of the train, v = 40 km/h = × 40 = 11.11 m/s. Time taken to attain the speed = 10 minutes = 10 × 60 = 600 sec. Acceleration of the train. Hence, Acceleration of the train is 0.0185 m/s².19-Jun-2017
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Answer:
Given parameters
Initial velocity (u) = 0
Final velocity (v) = 40 km/h
v = 40 × (5/18)
v = 11.1111 m/s
Time (t) = 10 minute
t = 60 x 10
t = 600 s
Acceleration (a) =?
Consider the formula
v = u + at
11.11 = 0 + a × 600
11,11 = 600 a
a = 11.11/600
a = 0.0185 ms-2
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