Find the area of the region bounded by the curves y=6-x*2and . y=x=4
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Answered by
4
Answer:
y=6-x*2 y=x=4
given 6-x =6 +1=5
given y=x=4 -5.5= 6+4=2 I think it is helpful so
Answered by
0
Answer:
Step-by-step explanation
Area under any curve = ∫ydx for range of x considered for the limits.
Intersection points of these two curves are found by solving as simultaneous equations.
y=6-x^2=x+4
x^2+x-2=0
x= -2 or 1
required area
= ∫(6-x^2)dx-∫(x+4)dx
=6x-x^3/3 -x^2/2-4x for limits x -2 to 1
=-x^3/3 -x^2/2+2x for limits x -2 to 1
=-((-2)^3-(1)^3)/3 -((-2)^2-(1)^2)/2+2(-2-1))
=3-1.5-6
=-4.5 sq units
Modulus 4.5 sq units(Answer)
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