Question

a train starting from a railway station and moving with a speed of 40 kilometre per hour in 10 minutes find its acceleration​

Answer 1

$\Large{\underline{\underline{\bf{\blue{Given}}}}}$

• Initial velocity =0{started from rest}
• Final velocity = 40km/h
• Time taken = 10min

$\Large{\underline{\underline{\bf{\blue{Find\:out}}}}}$

• Find the acceleration

$\Large{\underline{\underline{\bf{\blue{Solution}}}}}$

• Final velocity = 40 km/h

➞ v = 40 × 5/18

➞ v = 11.1 m/s

• Time taken = 10 min

➞ 1 min = 60 sec

➞ t = 10 × 60

➞ t = 600 sec

According to the first equation of motion

➞ v = u + at

➞ 11.1 = 0 + a*600

➞ 11.1 = 600a

➞ a = 11.1/600

➞ a = 0.0185 m/s²

Hence, the acceleration of train is 0.0185 m/s²

$\Large{\underline{\underline{\bf{\blue{Extra\: Information}}}}}$

• s = ut + ½ at² {2nd equation of motion}

• v² = u² + 2as {3rd equation of motion}

Answer 2

Answer:

Acceleration is 0.0185 m/s²

Explanation:

Given:

Initial velocity or u = 0

Final velocity or v = 40 km/h

= 40 x 5/18

= 11.11m/s

Time of journey or t = 10 minutes

= 10 x 60

= 600 seconds.

Acceleration or a = ?

To find:

v = u + at

11.11 = 0 + a x 600

11.11 = a x 600

a = $\frac{11.11}{600}$

a = 0.0185

Therefore, acceleration = 0.0185 m/s²

Acceleration :

Acceleration is the rate of change of velocity with time.

The SI unit of acceleration is metre per second square or m/s²

The C.G.S unit if acceleration is cm/s².