Question

a train starting from a railway station and moving with a uniform acceleration attains a speed of 40kmph in 10 minutes. calculate its acceleration.

Answer 1

V=u+at
40×5/18=0+a×10×60
100/9=600a
a=100/9×600
a=1/54=0.018m/s²

Answer 2

initial velocity=o
40 km/hr in m/sec = 11.11
time = 10min = 600sec
$acceleration \: = \: \frac{final \: velocty \: - \: intial \: velocty}{time} \\ a \: = \frac{11.11 - 0}{600} \\ a \: = 11.11 \frac{m}{ {sec}^{2} }$

here it is your ans