A train starting from a station and moves with a constant acceleration for 2 minutes. if it covers a distance of 400m in this period, find the acceleration
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hey dear
here is your answer
given data :
initial velocity (u) = 0
time taken (t) = 2 min. or 120 seconds
distance travelled (s) = 400 meter
to find : acceleration
here we go
solution :
by using 2nd equation of motion
s = ut+1/2at²
400 = 0*120+1/2*a*(120)²
400 = 0+1/2a*14400
7200a = 400
a = 0.055 m/s²
hope it helps :)
here is your answer
given data :
initial velocity (u) = 0
time taken (t) = 2 min. or 120 seconds
distance travelled (s) = 400 meter
to find : acceleration
here we go
solution :
by using 2nd equation of motion
s = ut+1/2at²
400 = 0*120+1/2*a*(120)²
400 = 0+1/2a*14400
7200a = 400
a = 0.055 m/s²
hope it helps :)
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