Question

a train starting from railway station and moving with uniform acceleration attains a speed of 40 km/h in 10 minutes. What is the acceleration?

Answer 1

u=0
v= 40km/h = 40*5/18 = 100/9m/s
t=10 min =10*60=600sec

a=v-u/t
a=100-0/600*9
a=1/54. =0.0185185185......

here is your correct answer.

Answer 2

Answer:

Known Terms:-

u = Initial speed

v = Final speed

a = Acceleration

t = Time

Given:-

Initial speed of the train, u = 0 km (Because train starts from the rest.)

Final speed of the train, v = 40 km/h = $\frac{5}{18}$ × 40 = 11.11 m/s.

Time taken to attain the speed = 10 minutes = 10 × 60 = 600 sec.

To Calculate:-

Acceleration of the train.

Formula to be used:-

⇒ $a=\frac{v-u}{t}$

Solution;-

Putting all the values, we get

⇒ $a=\frac{v-u}{t}$

⇒ $a=\frac{11.11-0}{600}$

⇒ $a=\frac{11.11}{600}$

⇒ $a=0.0185 \: m/s^2$

Hence, Acceleration of the train is 0.0185 m/s².