a train starting from railway station attain a spèd of 21m/sin one min find the acceleration
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Answered by
2
here u=0 , v=21m/s , t=1 min=60 seconds
Acceleration,a =(v-u)/t
a=(21-0)/60
a=21/60
a=7/20m/s^2
a=0.35 m/s^2
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Acceleration,a =(v-u)/t
a=(21-0)/60
a=21/60
a=7/20m/s^2
a=0.35 m/s^2
plz mark brainliest
KingAgr:
plz mark brainliest
this is not a full solution
how ?
maybe in the book the answer given is in decimal but this is also correct
But if u say I can calculatr it for u
ok
acceleartion is 7/20 m/s^2=0.35m/s^2
plz mark brainliest
Thanx for marking brainliest
ok
Answered by
2
hi frnd
in this case
initial velocity u =0
final velocity v=21 m/s
time=1min that is 60seconds
acceleration a=v-u/t
a=21-0/60
a=21/60
a=0.35 m/s²
i believe this will help u ;)
in this case
initial velocity u =0
final velocity v=21 m/s
time=1min that is 60seconds
acceleration a=v-u/t
a=21-0/60
a=21/60
a=0.35 m/s²
i believe this will help u ;)
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