A train starting from rest.A velocity of 90 km/h in 3 minutes. Assuming that the acceleration is unifrom.find the acceleration and the distance travelled by the train for attaining this velocity
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Answer:
Initial Velocity = u = 0 km/h
Final velocity = v = 90 km/h
Time = 5 min = 5/60 h = 1/12 h
Acceleration = a = ?
a = (v-u)/t
a = (90-0)/ (1/12)
= 90 ×12
= 1080 km/h²
Distance travelled = s = ut+ (1/2) at²
= 0x (1/12) + (1/2) × (1080) × (1/12)²
= (1/2) x1080x (1/144)
= 3.75km
∴ Distance travelled by the train = 3.75km.
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