A train starting from rest and moving with uniform acceleration attains a speed of 36 km per hour in 10 minutes find its acceleration
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36kmph=10m/s
and initial velocity u=0
t=10min=10×60=600sec
Using the equation
v=u+at
10=0+ 600a
or
a=10/600=0.0166m/s^2
and initial velocity u=0
t=10min=10×60=600sec
Using the equation
v=u+at
10=0+ 600a
or
a=10/600=0.0166m/s^2
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