Question

A train starting from rest at a high velocity of 72 km per hour in 5 minutes assuming that the acceleration is uniform find acceleration distance travelled by the train for attaining this velocity

Answer 1

U = 0

V = 72 km/h

V = 20 m / sec

t = 5 min

t = 300 sec

a = v - u / t

a = 20 - 0 / 300

a =  0.6667 m / sec sq

a = 0.67 m / sec sq

s = u t + 1 / 2 a t sq

s = 0 + 1 / 2 (O.67 ) 300 X 300

s = 30150 m