Question

A train starting from rest attain a speed of 72 km/h in 5 minutes find acceleration and the distance travelling by train

Answer 1

$v \: = u + at \ \\ 72 \times 5 \div 18 = 0 + a5 \times 60 \\ 20 = 300a \\ a = 1 \div15m \di \frac{m}{?} s {?$