find the largest number that divides 133 and 245 leaving a remainder 5 in each case
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largest number is 8
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Hii friend,
133 -5 = 128
245 -5 = 240
Prime factorisation of 128 = 2 × 2 ×2 × 2 × 2 × 2 × 2
Prime factorisation of 240 = 2 × 2 × 2 × 2 × 3 × 5.
HCF of 128 and 240 = 2 × 2 × 2 × 2 = 16
So,the required Number is the HCF of 128 and 240 is 16.
HOPE IT WILL HELP YOU...... :-)
HCF
133 -5 = 128
245 -5 = 240
Prime factorisation of 128 = 2 × 2 ×2 × 2 × 2 × 2 × 2
Prime factorisation of 240 = 2 × 2 × 2 × 2 × 3 × 5.
HCF of 128 and 240 = 2 × 2 × 2 × 2 = 16
So,the required Number is the HCF of 128 and 240 is 16.
HOPE IT WILL HELP YOU...... :-)
HCF
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