Question

a train starting from rest attains a velocity of 100km/hr in 10 minutes. If acc. is uniform find the acc. and distance covered by Train?​

Answer 1

Answer:

Given:-

Initial velocity ,u = 0m/s

Final velocity ,v = 100km/h = 100×5/18 = 27.77m/s

Time taken ,t = 10min = 10×60 = 600s

To Find:-

Acceleration ,a

Solution:-

We have to calculate the acceleration of the train. As we know that acceleration is defined as the rate of change in velocity.

a = v-u/t

where,

v is the final velocity

a is the acceleration

u is the initial velocity

t is the time taken

Substitute the value we get

:\implies:⟹ a = 27.77-0/600

:\implies:⟹ a = 27.77/600

:\implies:⟹ a = 0.046m/s²

Hence, the acceleration of the train is 0.046m/s².

Now, calculating the distance covered by the train. Using 3rd equation of motion

v² = u² + 2as

substitute the value we get

:\implies:⟹ 27.77² = 0² + 2×0.046 × s

:\implies:⟹ 771.1729 = 0 + 0.092 ×s

:\implies:⟹ 771.1729 = 0.092 ×s

:\implies:⟹ s = 771.1720/0.092

:\implies:⟹ s = ≈ 8382 m

Hence, the distance covered by the train is 8382 metres (approx)

I hope it will help you Ankit