Question

a train starting from rest attains a velocity of 108 km/h in 2 min. assuming the acceleration to be uniform find the value of (1) acceleration(2) distance covered

Answer 1

hope this helps you..

Answer 2

Given the data of initial velocity and final velocity and also given that the uniform acceleration, we can apply equation of motion that is first and second equation of motion.

Given data are, initial velocity u = 0m/s and final velocity v = 108km/h and time given as 2 min  

From the first equation of motion,

i) u = 0, v = 108 km/hr

$108\times \frac { 5 }{ 18 }=30m/s;\\t=2min=2\times 30=60\quad$

$a=\frac { v-u }{ t } =\frac { 30-u }{ 60 } =\frac { 1 }{ 2 } m/{ s }^{ 2 }$

To calculate distance

ii) $2as={v }^{ 2 }-{ u }^{ 2 };\\u = 0$

$s=\frac { { v }^{ 2 } }{ 2a }=\frac { { 30 }^{ 2 } }{ 2\times\frac { 1 }{ 2 }  }=900m$