A train starting from rest attains a velocity of 20m/s in 2 min. Assuming that the acceleration is uniform,find the distance travelled by the train while it attained this velocity
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2 min = 120s
v = u + at
20 = 0 + a*120
a = 20/120 = 1/6 m/s^2
S = ut + 0.5at^2
S = 0 + 0.5*1/6*(120)^2
S = 1200m
S = 1.2 km
Distance travelled while it attain 20m/s velocity is 1.2km
v = u + at
20 = 0 + a*120
a = 20/120 = 1/6 m/s^2
S = ut + 0.5at^2
S = 0 + 0.5*1/6*(120)^2
S = 1200m
S = 1.2 km
Distance travelled while it attain 20m/s velocity is 1.2km
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