Question

a train starting from rest attains a velocity of 72 km/hr in 5 minutes assuming that the acceleration is uniform,find the acceleration

Answer 1

hey your ans is here

______

given

u =0 (as it starts from rest)

v=72km/h--------m/sec
v=72×5/18
v=20

t=5min------sec
t=5×60
t=300

a=v-u/t
a=20-0/300
a=20/300
a=1/15 m/sec2
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Answer 2

Heya!!Here is your answer friend ⤵⤵
↔↔↔↔↔↔↔↔↔↔↔↔↔

Initial velocity u = 0 ( as it starts from rest )

Final velocity ,v = 72 km/hr = 72 ×5/18= 20 m/s.= ==

Time = 5 minutes = 5 ×60 = 300sec.

Acceleration A =
$\frac{v - u}{t} \\ putting \: in \: values \\ a = \frac{20 - 0}{300} \\ = \frac{20}{300} = \frac{1}{15} \\ = 0.06ms {}^{ - 2}$
Hope it helps you ✌✌