A train starting from rest attains a velocity of 72 kmh_1 in 5 min assuming that the acceleration in uniform find the acceleration and the distance travelled by the train for attaining this velocity
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Acceleration 0.06 m/secsqand distance 2700m
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distance =velocity*time.Convert velocity in metre per second.
acceleration =(final velocity - initial velocity)
____________________________
time
initial velocity=0
final velocity = 72km per hour
if initial velocity is more subtract final velocity from initial velocity
acceleration =(final velocity - initial velocity)
____________________________
time
initial velocity=0
final velocity = 72km per hour
if initial velocity is more subtract final velocity from initial velocity
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