Question

a train starting from rest attains a velocity of 72km/h in 5 min .asumming the acceleration is uniform find . the acceleration, the distance traveled by the train for attending this velocity

Answer 1

Initial velocity, u =0
Time, t = 5*60= 300 s
Final velocity, v = 72 kmph = 72* (5/18) m/s = 20 m/s
v = u + at
20 = 0 + a*300
a = 1/15 metre/second square
$v^{2} - u ^{2} = 2as$
400-0 = 2*(1/15)*s
s = 3000m or 3 km