Question

find three numbers in AP whose sum is 15 and product is 80

Answer 1

let's three numbers be a - d, a, a + d. Its sum is equal to 15 so a will be 5. Its product is equal to 80. Multiply them and u will get d =+-3. Then substitute the values and get 3 numbers

Answer 2

Let the three no. be (a+d),a, (a-d)
(a+d)+a+(a-d)=15
3a=15
a=5... (i)
(a+d)(a)(a-d)=80
(a^2-d^2)(a)=80
putting the value of (a)
we get,
(5^2-d^2)(5)=80
25-d^2=16
d^2=9
d=3
hence AP is
5,8,11,14.....