A train starting from rest attains a velocity of 72km/hr in 5minute . assuming that the acceleration is uniform , find - a) the acceleration b) the distance travelled by the train for attaining this velocity.
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Answered by
182
u=0 m/s
v=72 km/h=20m/s
t=5 min=300s
a=(v-u)/t=(20-0)/300=20/300=1/15 m/s2
s=ut+1/2 at2
=0+1/2×1/15×300×300
=1/30×300×300
=3000 m=3 km
Plz mark as brainliest :D
v=72 km/h=20m/s
t=5 min=300s
a=(v-u)/t=(20-0)/300=20/300=1/15 m/s2
s=ut+1/2 at2
=0+1/2×1/15×300×300
=1/30×300×300
=3000 m=3 km
Plz mark as brainliest :D
Answered by
33
v=u+at
20=0+a×300
a=1/15
s=ut+1/2at^2
= 0+1/2×1/15×300×300
=3000m
=3 km
HOPE THIS HELPS YOU
BRAINY STUDENT
20=0+a×300
a=1/15
s=ut+1/2at^2
= 0+1/2×1/15×300×300
=3000m
=3 km
HOPE THIS HELPS YOU
BRAINY STUDENT
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