A train starting from rest attains a velocity of 90 km\h in 3m. assuming that the acceleration is uniform,fid out the (i) acceleration and (ii)the distance traveled by the train for attending this velocity
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79
ʜᴇʟʟᴏ ᴍᴀᴛᴇ!
Here, u ( initial velocity ) = 0
v ( Final Velocity ) = 90 km/h
t ( time taken ) = 3 min
First, bring all units same.
3 min = 3 × 60 s = 180 s
90 km/h = 90 × 5/18 = 25 m/s
v = u + at
25 = 0 + a(180)
25/180 = a
0.14 m/s² = a
s = ut + 1/2 ( at² )
s = (0)(180) + 1/2 (0.14)(180)(180)
s = (0.14)(90)(180)
s = 2268 m
ʜᴇɴᴄᴇ, (ɪ) 0.14 ᴍ/s² ᴀɴᴅ (ɪɪ) 2268 ᴍ
Hope it helps
Here, u ( initial velocity ) = 0
v ( Final Velocity ) = 90 km/h
t ( time taken ) = 3 min
First, bring all units same.
3 min = 3 × 60 s = 180 s
90 km/h = 90 × 5/18 = 25 m/s
v = u + at
25 = 0 + a(180)
25/180 = a
0.14 m/s² = a
s = ut + 1/2 ( at² )
s = (0)(180) + 1/2 (0.14)(180)(180)
s = (0.14)(90)(180)
s = 2268 m
ʜᴇɴᴄᴇ, (ɪ) 0.14 ᴍ/s² ᴀɴᴅ (ɪɪ) 2268 ᴍ
Hope it helps
Answered by
6
hey !!!
hope it helps Nd if any mistake so sorry then ....
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