a train starting from rest attains a velocity of72 km h in 5 minutes . assuming that acceleration is uniform find the acceleration and the distance travelled by the train to attain this velocity
nishantsingh894:
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u=0
v=72km/h=20m/s.
t=5mins=300s.
a=v-u/t=20/300=2/30=1/15m/s2=0.06m/s2.
2as=v2-u2.
2as=v2-0
s=v2/2a=20/2*1/15=3000m=3km.
hope it helps.
#aditya
v=72km/h=20m/s.
t=5mins=300s.
a=v-u/t=20/300=2/30=1/15m/s2=0.06m/s2.
2as=v2-u2.
2as=v2-0
s=v2/2a=20/2*1/15=3000m=3km.
hope it helps.
#aditya
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