Physics, asked by nkharish004, 1 year ago

a train starting from rest attains a velocity of72 km h in 5 minutes . assuming that acceleration is uniform find the acceleration and the distance travelled by the train to attain this velocity


nishantsingh894: What is the answer of this question
Sanskriti141: acceleration is 6.66m/s^2
MonsieurBrainly: a=0.06m/s2
MonsieurBrainly: distance =3km=3000m
Sanskriti141: sorry that only
MonsieurBrainly: 9th th example
MonsieurBrainly: tb
Sanskriti141: yup

Answers

Answered by MonsieurBrainly
2
u=0
v=72km/h=20m/s.
t=5mins=300s.
a=v-u/t=20/300=2/30=1/15m/s2=0.06m/s2.
2as=v2-u2.
2as=v2-0
s=v2/2a=20/2*1/15=3000m=3km.

hope it helps.
#aditya
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