Question

A train starting from rest attains velocity of 144km/h in 10min assuming acceleration.What is the acceleration and distance travelled by the train?

Answer 1

$\huge{\bf{SOLUTION:-}}$

Given-

u = 0

v = 144km/h = $\frac{144\times 1000}{3600}$ = 40m/s

t = 10 min = 600 seconds

a = ?

s = ?

Formula used:-

$\star{\boxed{v=u+at}}$

$\star{\boxed{s=ut+{\frac{1}{2}}at^{2}}}$

Solution:-

To find acceleration

v = u + at

40 = 0 + a×600

40 = 600a

a = 40/600

a = 1/15

a = 0.0667 $ms^{-2}$

To find distance

s = 0×600 + $\frac{1}{2}$ × $\frac{1}{15}$ × 600 × 600

s = 0 + 12000

s = 12,000m

s = 12km