Question

A train starting from rest move with a uniform acceleration of 0.2m/s for 5min calculate the speed acquired and th distance travelled in this time?

Answer 1

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$Given \: that : \\ \\ Initial \: speed(u) = 0 m/ \: s \\ time \: taken \: = 5min \: = 300sec \\ Uniform \: Acceleration(a) = 0.2m/ \: s^2 \\ \\ \: Using \: first \: equation \: of \: motion : \\ v = u + 2at \\ v = 0 + 0.2 \times 300 \\ v = 60ms \\ \\ So, \: The \: aquired \: speed \: is \: 60m/s ... \\ \\ Now, \: Using \: 3rd \: equation \: of \: motion : \\ \\ = > s = ut + \frac{1}{2} at {}^{2} \\ \\ = > s = 0 + \frac{1}{2} \times 0.2 \times 300 \times 300 \\ \\ = > s = \frac{18000}{2} \\ \\ = > s = 9000m$

HENCE , The distance covered by train is 9km....
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