Question

a train starting from rest moves with a uniform acceleration of 0.2m/s^2 for 5 minutes calculate the speed acquired and the distance travelled in this time

Answer 1

here acc = 0.2
time = 5 *60 sec
v =u + at
v = 0 + 2/10 x 300
v = 60 m/s
now for distanvce
s = ut + 1/2at2
s= 0 + 1/2 x 0.2 x 300x300
s = 900 m