A train starting from rest moves with a uniform acceleration of 0.2 m/s square for 5min calculate the speed acquired and the distance travelled in this time
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time taken = 5 min = 300 s
let final speed = v
then,
use kinematics equation ,
v = u + at
= 0 + 0.2 × 300 = 60 m/s
and distance travelled = S ( let )
use formula ,
S = ut + 1/2at²
= 0 + 1/2 × 0.2 × (300)²
=0.1 × 90000
=9000 m
= 9 km
Hope it will help you
let final speed = v
then,
use kinematics equation ,
v = u + at
= 0 + 0.2 × 300 = 60 m/s
and distance travelled = S ( let )
use formula ,
S = ut + 1/2at²
= 0 + 1/2 × 0.2 × (300)²
=0.1 × 90000
=9000 m
= 9 km
Hope it will help you
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