Question

a train starting from rest moves with a uniform acceleration of 0.2 M per second sq for 5 minutes calculate the speed and distance travelled in this time

Answer 1

heyy frend here's ur ans
given= u= 0m
a =0.2 m/sec sq.
t = 5 min=300sec
s(distance)= ut+1/2*at square
= 0*300 + 1/2 * 0.2*300*300
=1/2 * 0.2*300*300
=0.1 *90000
=9000 meters
speed = distance /time
= 9000/300
=30m/s
hope it will help